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x^2-15x+36=68
We move all terms to the left:
x^2-15x+36-(68)=0
We add all the numbers together, and all the variables
x^2-15x-32=0
a = 1; b = -15; c = -32;
Δ = b2-4ac
Δ = -152-4·1·(-32)
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{353}}{2*1}=\frac{15-\sqrt{353}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{353}}{2*1}=\frac{15+\sqrt{353}}{2} $
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